
Prove that $T^*$ is injective iff $ImT$ Is dense
Dec 21, 2014 · Let X,Y be two normed spaces, and $T:X\rightarrow Y$ a bounded linear operator. prove that the adjoint operator $T^*$ ($T^*f (x)=f (Tx)$ is injective iff $ImT$ is dense
linear algebra - if $T: V\to V$ and $ dim (KerT)+dim (ImT)=dimV
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V = ImT \oplus \ KerT - Mathematics Stack Exchange
Linear Tranformation that preserves Direct sum $ V = ImT \oplus \ KerT $ Ask Question Asked 12 years, 10 months ago Modified 12 years, 10 months ago
Find Base for ImT and KerT - Mathematics Stack Exchange
Linear Alegbra - Find Base for ImT and KerT Ask Question Asked 11 years ago Modified 11 years ago
Find a basis for KerT and ImT (T is a linear transformation)
Jun 15, 2019 · Find a basis for KerT and ImT (T is a linear transformation) Ask Question Asked 6 years, 5 months ago Modified 6 years, 5 months ago
linear algebra - Prove Ker$T= ($Im$T^*)^\bot$ and …
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Show that $ImT^t= (kerT)°$ - Mathematics Stack Exchange
Mar 1, 2015 · Let $T:V→W$ be linear transformation and V have a finite dimension. Show that $ImT^t=(kerT)°$ I have to prove it by mutual inclusion. I have proven the first ...
Intersection of the NullT and ImT - Mathematics Stack Exchange
Feb 11, 2015 · Intersection of the NullT and ImT Ask Question Asked 10 years, 7 months ago Modified 4 years, 7 months ago
Finding the basis of ker (T) and im (T) - Mathematics Stack Exchange
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Example of linear transformation on infinite dimensional vector …
May 22, 2018 · I haven't had much experience with infinite dimensional vector spaces, and I was working on a problem that asks to prove that for a finite dimensional vector space $V$, and …